Which of the following represents the equivalent weight of KHC2O4•H2C2O4•2H2O as an acid and as reducing agent, respectively?
A. 84.73/63.55
B. none of the given answers
C. 63.55/85.03
D. 127.55/127.55
E. 63.55/85.03
As we know,
"Equivalent weight(E) = M\/valency factor"
Valency factor for acid is number of ionizable H+ ions. And for reducing agent is change in oxidation number.
So, for as an acid
E =127.55
As an reducing agent
E = 127.55/2 = 63.55
So, [B] is correct.
[None of the given answers]
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