How much NH 4 OH will be needed to produce a 650-mL 0.45 M solution?
Volume = 650 ml = 0.650L
Molarity = 0.45M
Molarity = no. of moles / volume (in litres)
0.45 = moles/0.650
moles = 0.2925
1 moles NH4OH contains = 35.0458 g
0.2925 moles of NH4OH contains =
35.0458×0.2925 = 10.2508965g
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