If you are given 150 grams of C4H10 ,How many grams of O2 would you need to completely react with the C4H10 ?
2C4H110g)+13O2(g)→8CO2(g)+10H2O(g).
2 mole of C4H110reacts with 13 O2
no. of moles in 150g of C4H10 150/58 = 2.58 moles
no. of moles of O2 required = 16.81 moles
mass of O2 required = 16.81×32
= 537.9 g
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