Assume you have 7.21 m solution that raised the boiling point of the solution by 1.25°C. What is the molal boiling point constant (Kb) for the solution?
We know the formula, ∆T = kf m
Where, ∆T = boiling point elevation constant(K)
= 1.25°C
= 1.25 K (as Kelvin and celcius scale have same interval)
kf = molal boiling point elevation constant
m = molality of the solution
So, from the above equation,
kf = ∆T/m
= 1.25/7.21
=0.1734 K.kg.mol-1
Hence the required answer is = 0.1734 K.kg.mol-1
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