Question

9.8 Ammonia is produced by the reaction of nitrogen and hydrogen

N3(g) +3H2(g) - 2NH3(g)

Ammonia

a. How many moles of H2 are needed to react with 1.8 mol of N2?

Answer 1

N₂(g) +3H₂(g) $\to$ 2NH₃(g)

If 1=1.8moles

$\therefore$ 3=3×1.8

=5.4moles of H₂