Answer to Question #157080 in General Chemistry for pri

Question

Suppose a bicycle tire is inflated to a pressure of 70.0 kPa at 25 °C. If the bicycle is taken outside, where the temperature is -3 °C, what is the new pressure of the gas inside the tire? Assume the volume and amount of gas remain constant. Show your work and explain each step

Answer 1

$P_1 = 70.0 \;kPa \\ T_1 = 25 + 273 = 298 \;K \\ T_2 = -3 + 273 = 270 \;K \\ V = constant \\ \frac{P_1}{T_1} = \frac{P_2}{T_2} \\ P_2 = \frac{P_1 \times T_2}{T_1} \\ = \frac{70.0 \times 270}{298} \\ = 68.42 \;kPa$

Answer: 68.42 kPa