C is a sulution containing 3.20 g of H2X in 500cm3 D is a solution containing 0.107 moldm-3 KOH. in an acid base titration 25.0cm3 of D is required an average of 20.55cm3 of C for complete neutralization calculate the concentration of C in gdm-3
Proportion:
3.20 g – 500 cm3
x – 1000 cm3 (dm3)
"x = \\frac{3.20 \\times 1000}{500} = 6.40 \\;g"
Answer: 6.40 g/dm3
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