Question

C is a sulution containing 3.20 g of H2X in 500cm3 D is a solution containing 0.107 moldm-3 KOH. in an acid base titration 25.0cm3 of D is required an average of 20.55cm3 of C for complete neutralization calculate the concentration of C in gdm-3

Answer 1

Proportion:

3.20 g – 500 cm³

x – 1000 cm³ (dm³)

$x = \frac{3.20 \times 1000}{500} = 6.40 \;g$

Answer: 6.40 g/dm³