A crystalline xenon fluoride molecule (XeF) can be produced by heating Xe and F together at high temperature. Xenon gas (0.12 atm) is added to a 0.25 L container at 273 K followed by enough F give a total pressure of 0.72 atm. The reaction is heated until complete, and then cooled back to 273 K; the pressure is now 0.36 atm. At the end of the reaction the gas mixture is analyzed and found to contain only fluorine. What is the empirical formula of the xenon fluoride formed during this reaction? Your answer should be in the form: Xe#F#
Xe(g) + 2F2(g) → XeF4(s)
Answer: XeF4
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