Answer to Question #156452 in General Chemistry for shama

Question

A gas has a volume of 35 ml at 15oC. If the volume changes to 40 ml, what is the new temperature?  ( answer in kelvin )    

Answer 1

According to Gay-Lussac's law, at constant pressure, the volume of a gas changes in proportion to the temperature аccording to the following formula:

$V1/T1 = V2/T2$

V1 is the initial volume of gas at temperature T1

V2 is the volume we are looking for at temperature T2

Let's substitute our data into the formula:

$V1 =35ml, T1= 288K, V2 = 75 ml$

$35/288=75/T2$

$T2= 75×288/35$

$T2 = 617K$

Answer: the new temperature will be 617K