Answer to Question #155789 in General Chemistry for Liseth

Question #155789

Calculate the specific heat of a 34 g sample of metal if it absorbs 7500 Jules of he and his temperature changes 24°C

Expert's answer

c = Q/m/"\\Delta"T = (7500 J)/(34 g)/(24 °C) = 9.19118 J/g/°C = 9191.18 J/kg/°C

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