Question #155579
How many moles of CO2 are produced when 10.0 mol of C3H8 are burned in excess of oxygen in a gas grill?
Expert's answer
Given that 10.0mol of C3H8burns in excess Oxygen to produce CO2 and water, the equation will be as follows:
C3H8+ 5O2 = 3CO2 + 4H2O
Mol ratio of C3H8 to CO2 is 1:3, therefore;
Moles of C22 = 3.0mol(CO2)× 10mol(C3H8)/1.0mol(C3H8)
Moles of CO2 produced = 30.0 moles
