Answer to Question #155541 in General Chemistry for Dede

Question

If the soda can was at a pressure of 160.3 kPa at 393K, what was the pressure at 258K when it imploded if the volume was the same before and after?

Answer 1

$\frac{P_1}{T_1}$ = $\frac{P_2}{T_2}$ , P₁ = 160.3kPa , T₁ = 393K , P₂ = ? , T₂ = 258K

$\frac{160.3}{393}$ = $\frac{P_2}{258}$

P₂ = $\frac{258×160.3}{393}$

P₂ = 105.23kPa