Answer to Question #155238 in General Chemistry for Caden

Question

Al + ?HCl → ?AlCl₃ + ?H₂

Use the equation above to answer the following questions:

How many moles of Al would you need to react with 9 moles of HCl?  mol Al

How many moles of HCl would you need to make 6.5 moles of H₂? 3.265 mol HCl

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Question 2 (10 points)

?CO₂ + ?H₂O → ?C₆H₁₂O₆ + ?O₂

Use the equation above to answer the following questions:

How many moles of C₆H₁₂O₆ would be produced if 24 moles of CO₂are used? 4 moles C₆H₁₂O₆

How many moles of H₂O would be needed to make 1.5 moles of O₂?   moles H₂O

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Question 3 (10 points)

4Al + 3O₂ → 2Al₂O₃

Using the equation above, answer the following questions:

How many moles of O₂ would you need to react with 10 moles of Al?  mol O₂

How many moles of Al woul you need to make 6 moles of Al₂O₃? 4.5 mol Al

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Question 4 (10 points)

?Mg(NO₃)₂ + ?NaCl → ?MgCl₂ + ?NaNO₃

Use the equation above to answer the following questions:

How many moles of NaCl do you need to react with 5 moles of Mg(NO₃)₂?

   mole NaCl

How many moles of MgCl₂ could you make with 12 moles of NaCl?

   moles MgCl₂

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Question 5 (10 points)

?N₂ + ?H₂ → ?NH₃

Use the equation above to answer the following questions:

How many moles of H₂ do you need to react with 3.4 moles of N₂?   moles H₂

How many moles of NH₃ could you make with 9 moles of H₂?   moles NH₃

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Question 6 (10 points)

2Al + 3I₂ → 2AlI₃

Use the equation above to answer the following questions:

How many moles of I₂ do you need to react with 9 moles of Al?   mol I₂

How many moles of AlI₃ could you make with 8 moles of I₂?   mol AlI₃ (Use 3 Sig figs)

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Question 7 (10 points)

?KClO₃ → ?KCl + ?O₂

Use the equation above to answer the following questions:

How many moles of KClO₃ will it take to make 6 moles of KCl? 9 mol KClO₃

How many moles of O₂ can be made with 2.5 moles of KClO₃?   mol O₂

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Answer 1

Question 1.

3 moles of Al

13moles of HCl

Question 2.

24moles of C₆H₁₂O_6, 4mol C₆H₁₂O₆

1.5moles of H₂O

Question 3.

7.5moles of O₂

12moles of Al

follow the trend for the rest