Answer to Question #154831 in General Chemistry for its me gel

Question

Identify the anode and cathode using redox half-reaction and balance the equation. Indicate the cell notation.

1. Sn ⁺⁴ + Fe ⁺² → Sn⁺² + Fe⁺³

Answer 1

Sn⁺⁴ + 2e^- ---------Sn⁺²(reduction half equation)

Fe⁺² ----------Fe⁺³ +e^- (oxidation half equation)

Balancing the equation we have;

Sn⁺⁴+2Fe⁺²---------Sn⁺²+2Fe⁺³

The Fe⁺² is the anode because oxidation takes place there while the Sn⁺⁴ is the cathode because reduction takes place there.

The cells notation is written as;

Fe⁺²/Fe⁺³//Sn⁺⁴/Sn⁺²