Answer to Question #154823 in General Chemistry for Hallie Morgan

Question #154823
Using the following reaction: 6 NaCl + Ba3(PO4)2 —> 2 Na3PO4 + 3BaCl2

How much barium chloride is produced (in g) when 750 g of sodium chloride react with excess barium phosphate?

1
Expert's answer
2021-01-12T07:00:59-0500

The balanced chemical reaction is 3BaCl2​+2Na3​PO4​→Ba3​(PO4​)2​+6NaCl.

0.5 moles of barium chloride will require= "\\frac{(0.5)\\times(2)}{3} = 0.33"

However, only 0.2 moles of sodium phosphate are present.


Thus, sodium phosphate is the limiting reagent.


2 moles of sodium phosphate produce 1 mole of barium phosphate.


Thus, 0.2 moles of sodium phosphate will produce 0.1 mole of barium phosphate.



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