Question

Using the following reaction: 6 NaCl + Ba3(PO4)2 —> 2 Na3PO4 + 3BaCl2

How much barium chloride is produced (in g) when 750 g of sodium chloride react with excess barium phosphate?

Answer 1

The balanced chemical reaction is 3BaCl2​+2Na3​PO4​→Ba3​(PO4​)2​+6NaCl.

0.5 moles of barium chloride will require= $\frac{(0.5)\times(2)}{3} = 0.33$

However, only 0.2 moles of sodium phosphate are present.

Thus, sodium phosphate is the limiting reagent.

2 moles of sodium phosphate produce 1 mole of barium phosphate.

Thus, 0.2 moles of sodium phosphate will produce 0.1 mole of barium phosphate.