Question

How many grams of H₃PO₄ are produced when 10.0 moles of water react with an excess of P₄O₁₀

Answer 1

P₄O_{10 (s)} + 6 H₂O _(l) $\to$ 4 H₃PO_{4 (aq)}

10 mole H₂O($\frac{4mole H_3PO_4}{6moleH_2O}$ ) =

40/6 mole of H₃PO₄

Mass of H₃PO₄ = $\frac{40}{6}$ ×98 grams = 653.33 g