How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10
P4O10 (s) + 6 H2O (l) "\\to" 4 H3PO4 (aq)
10 mole H2O("\\frac{4mole H_3PO_4}{6moleH_2O}" ) =
40/6 mole of H3PO4
Mass of H3PO4 = "\\frac{40}{6}" ×98 grams = 653.33 g
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