Question #154402

If you want to delay a pulse of light in a laser experiment, you can send the light through a long coil of fiber optic cable. Light travels somewhat slower in the glass core of a fiber than it does in vacuum. We will approximate the speed of light in the fiber as 2.04 x 10m/s. What length of fiber (in meters) does the light travel in 168 ns?



1
Expert's answer
2021-01-11T03:50:45-0500

Time taken by a certain particle to cover a certain length or distance in particular speed is given by the formula

Distance=speed×timeDistance = speed \times time

Here, the particle is light

Speed of light in optical fibre =2.04×108  m/s= 2.04 \times 10^{8} \; m/s

Amount of time need to be delayed = 168 ns

=168×109  s=1.68×107  s= 168 \times 10^{-9} \; s \\ = 1.68 \times 10^{-7} \; s

The length of optical fibre required = Speed of light in optical fibre x amount of time to be delayed

=2.04×108×1.68×107  m=34.27  m= 2.04 \times 10^8 \times 1.68 \times 10^{-7} \; m \\ = 34.27 \;m

Answer: 34.27 m


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