Determine the amount of chloride in 10.0 g of barium chloride.
M("BaCl_2") - 208 "\\frac{g} {mole}"
In the given chemical compaunds, we have 2 chlorine atoms :
208 "\\frac{g} {mole}" - 71 "\\frac{g} {mole}"
10 g - x g
x= "\\dfrac{10\\cdot 71} {208} = 3.41 g"
The amount of chlorine in the 10 g of barium chloride is 3.41 g.
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