Question

Determine the amount of chloride in 10.0 g of barium chloride. 

Answer 1

Solution:

M($BaCl_2$) - 208 $\frac{g} {mole}$

In the given chemical compaunds, we have 2 chlorine atoms :

208 $\frac{g} {mole}$ - 71 $\frac{g} {mole}$

10 g - x g

x= $\dfrac{10\cdot 71} {208} = 3.41 g$

Answer:

The amount of chlorine in the 10 g of barium chloride is 3.41 g.