What is the density of oxygen o2 in grams per liter at 25°c and 0.85 atm
Assuming you have 1mole of oxygen.
The volume of 1 mole of oxygen at stp = 22.4L
Mass of 1 mole of oxygen = 16g
stp means that temperature is 25oC and pressure is 1 atm.
In this case, the temperature remains the same (25oC) but pressure reduces.
We need to find the new volume of the gas at the reduced pressure.
We use Boyles Law;
P1V1 = P2V2
P1= 1 atm
P2 = 0.85 atm
V1 = 22.4L
V2 =?
V2 = "\\dfrac{P1V1}{P2} = \\dfrac{1atm x 22.4L}{0.85atm} = 26.353L"
Density = "\\dfrac{mass}{volume} = \\dfrac{16g}{26.353L} = 0.607g\/L"
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