What is the percent composition (by mass) of nitrogen in N2S2?
Molar mass of N2S2 = (14x2) + (32x2) = 92g/mol
Molar mass of nitrogen in N2S2 = 14 x2 = 28g/mol
% by mass of nitrogen = "\\dfrac{28g\/mol}{92g\/mol}x100" = 30.43%
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment