calculate the percent by mass of solute at 25.0 g of potassium carbonate in 100.0 g of water.
%K2CO3 = 25.0g100.0g+25.0g×100%=20.0%\frac{25.0g}{100.0g+25.0g}\times100\%=20.0\%100.0g+25.0g25.0g×100%=20.0%
Answer: 20.0%
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