A cup of coffee (131 g) cools from 85˚C down to comfortable room temperature 24˚C. How much energy (q) does it release to the surroundings?
q = m c ΔT
q = energy , m = mass = 131g
c = specific hear ( for coffie) = 4.184 J/g ⁰C
ΔT = 85⁰ - 24⁰ = 61⁰ C
q = m c ΔT
q = 131 × 4.184 × 61
q = 33,434.344 joule
q = 33.43 KJ
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