Calculate the percent error for your percent by mass of NaClO in the commercial bleachÂ
Data Table Molarity of Na2S2O3 0.125 M
Initial Buret Reading (Na2S2O3) 1.50 mL
Final Buret Reading (Na2S2O3) 14.35 mLÂ
Molarity of Na2S2O3= 0.125M
Volume of Na2S2O3= 14.35ml - 1.50ml= 12.85ml
Molar mass of Na2S2O3= 158gmol-1
Mole= C x V
Mole= 0.125 x 12.85/1000 = 0.0016mol
Mass of Na2S2O3= mole x molar mass
= 0.0016 x 158= 0.25g
Density of the bleach=1.08g/ml
Mass of bleach= density of bleach x Volume
= 1.08 x 12.85=13.88g
Percentage by mass of Na2S2O3 present= 0.25/13.88 x 100% = 1.8%
According to the question, if NaClO is the other substance present in the bleach, then the percentage by mass of NaClO will be = 100 - 1.8 = 98.2%
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