Question

In the equation ( NO2 -- N2O5 + NO) 0.050 mol/l of NO2 exists at equilibrium what is the concentration of N2O5 at equilibrium

Answer 1

Balance the equation

3NO₂ $\to$ N₂O₅ + NO

The Formula for K_c = [N₂O₅][NO]/[NO]³

We know that K_c is constant for a given reaction and for the given equation

[N₂O₅] = [NO]

$\implies$ concentration of N₂O₅ =$\sqrt{[NO2]^3 *Kc}$ = $\sqrt{(0.05)^3 * Kc}$