Question

You have a tank or argon gas at 19.8 atm pressure at 19 0C. The volume of argon in the tank is 50.0 L. What would be the volume of this gas if you allowed it to expand to the pressure of the surrounding air (0.974 atm) ?

Answer 1

P1=19.8 atm, Tc=292.15K, V1=0.05m3, P2= 0.974atm.

$P1V1=P2V2$

V2= (19.8*0.05)/0.974

V2=1.016m3