"n(HNO_3) = \\frac{18.5}{63}=0.293 \\;mol \\\\\n\nn(Fe(NO_3)_3) = n(HNO_3)=0.293 \\;mol \\\\\n\nm(Fe(NO_3)_3) = 0.293 \\times 242 = 71.06 \\;g"
Proportion:
71.06 – 100 %
21.25 – x
"x = \\frac{21.25 \\times 100}{71.06}=29.9" %
Answer: 30 %
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