Answer to Question #151274 in General Chemistry for Rori

Question

How many grams of CaO will be produced from the decomposition of 1.44 x 10^23 molecules of CaCO3

Answer 1

CaO is produced by reaction:

CaCO₃ = CaO + CO₂

One mole of any substance contains 6.022×10²³ atoms/molecules (N_a).

Hence,

n(CaCO₃) = (1.44×10²³ molecules of CaCO₃) × (1 mol / 6.022×10²³ molecules) = 0.239 moles CaCO₃

According to the equation: n(CaCO₃) = n(CO₂)

Thus:

n(CO₂) = n(CaCO₃) = 0.239 moles

Moles of CaO = Mass of CaO / Molar mass of CaO

The molar mass of CaO is 56.077 g mol^-1.

Hence,

Mass of CaO = Moles of CaO × Molar mass of CaO

Mass of CaO = 0.239 mol × 56.077 g mol^-1 = 13.4 g

Mass of CaO is 13.4 grams.

Answer: 13.4 grams of CaO