Answer to Question #151196 in General Chemistry for Javier

Question

Calculate the heat change in calories for condensation of 13.0 g steam at 100 C.

Please express answer as a positive value using three significant figures and include the appropriate units.

Answer 1

Specific latent heat of vaporization of water at 100°C = 2260 J/g

Heat change = (13.0 g) × (2260 J/g) = 29380 J = 7022 cal;

Answer: 7022 calories