Question

What are the mole fractions of solute and solvent in 1.00 m aqueous solution?

Answer 1

Solution:1.0 m (Molal) solution implies that 1 mole of the solute is dissolved in 1000 g of the solvent (water):

1)

$mole\;fraction\;of\;solute= \dfrac{1\;mole}{1\;mole\;+\; \tfrac{1000g}{18( \tfrac{g}{mole} )} }= \dfrac{1}{56.5} =0.0177$

2)

$x_{solute}\;+\;x_{solvent}=1$

$x_{solvent}=1-0.0177\;=0.9823$

$Answer:$

$x_{solute}=0.0177$

$x_{solvent}=\;0.9823$