∆T=iKbm.
m=∆T/iKb. = 8.3/3 x 1.86 = 1,4874552 mol/kg.
m=moles of solute/kg of solvent.
1,4874552 x 0.3 = 0,44623656.
0,44623656 x 208 = 92,8172045 g of BaCl2.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment