Question #150894

The element boron has two naturally occurring isotopes with masses of 10.0129 amu and 11.0093 amu. What is the fractional abundance of the second isotope?


1
Expert's answer
2020-12-14T14:46:42-0500

10x+(1−x)(11)=10.0110x+11−11x=10.01−x=−0.99x=99theabundanceofB10=9910x + (1-x) (11) = 10.01\newline 10x + 11 -11x =10.01\newline -x = -0.99\newline x= 99\newline the abundance of B10=99%\newline abundance of B11 =1%


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