The enthalpy of formation of ethanol,C2H5OH, is −277.0 kJ/mol at 298.15 K. Calculate the enthalpy of combustion of one mole of ethanol, assuming that the products are CO2(g) and H2O(l). standard enthalpy of formation of carbon dioxide and water are −393.5 kJ, −285.8 kJ respectively.Required to answer. Single choice.
C2H5OH + 3O2 = 2CO2 + 3H2O
∆H= (2 x (-393.5) + 3 x -(285.8)) - (-277) = -1 367,4 kJ/mol.
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