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Answer to Question #149905 in General Chemistry for Bri

Question #149905
Calculate the mass of water produced when 6.48 g of butane reacts with excess oxygen.
1
Expert's answer
2020-12-10T07:49:04-0500

C4H10 + 5.5O2 --------4CO2 + 5H2O

If 6.48g of butane react =(6.48/58)= 0.11moles

Then 0.55moles of water are produced from the reaction, which is equivalent to;

"(0.55\/1)\u00d7 18 =" 9.9 g


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