Answer to Question #149872 in General Chemistry for carrot

Question #149872

How many particles of PbCl₂ are present in 2.25 kg of it? (MM: 278.1 g/mol)

Expert's answer

If 1mole of PbCl2 contains 278.1g

2.25 kg= 2250g

This is equivalent to ( 2250/278.1)=8.1moles

If 1mole contains 6.022×10²³particles

Then 8 moles contain; = 4.9×10²⁴ particles

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