90 g of lithium hydroxide is neutralize with the excess sulfuric acid. How many grams of lithium sulfate will be produced?
2LiOH + H2SO4 = Li2SO4 + 2H2O
2LiOH = Li2SO4
2(24)g LiOH = 110g Li2SO4
1g LiOH = 110/(2 x 24) g Li2SO4
90g LiOH = 110 x 90/(2 x 24) g Li2SO4
= 206.25 Li2SO4
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