"HA + H_2O \\to A^- + H_3O^+"
|HA| = |CH3COOH| = 2.0M
|A-| = |CH3COO-| = 2.0M
Ka = 1.8 x10ˉ⁵
pKa = -logKa = -log(1.8 x10ˉ⁵) = 4.74
From, pH = pKa + log|A-|/|HA|
pH = 4.74 + log2/2 = 4.74 + log1
pH = 4.74 + 0
pH = 4.74
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