Answer to Question #149049 in General Chemistry for Tisha

Question #149049

How man grams of magnesium cyanide are needed to make 275 mL of a 0.075 M solution?

Expert's answer

n(Mg(CN)₂) = V*c = (0.275 L)*(0.075 M) = 0.020625 mol

m(Mg(CN)2) = Mr(Mg(CN)2)*n(Mg(CN)2) = (76.3398 g/mol)*(0.020625 mol) = 1.5745 g.

Learn more about our help with Assignments: Chemistry

No comments. Be the first!

Who Can Help Me with My Assignment

There are three certainties in this world: Death, Taxes and Homework Assignments. No matter where you study, and no matter…
How to Finish Assignments When You Can’t

Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
How to Effectively Study for a Math Test

Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…