Answer to Question #149027 in General Chemistry for Joey Farley

Question

Starting with 26.3 g of copper (ll) chloride and 4.62 moles of mercury (l) sulfate
Actual yield must be in grams

Answer 1

Actual yield is;

$26.3CuCl \times 1mol CuCl\over 98.99g/mol CuCl$ $=0.2656gCuCl$

$0.2656\times$ $295.70g/mol Ag_2SO_3\over 1mol Ag_2SO_3$ $=17.01g$

The actual yield$=17.01g$