Answer to Question #148715 in General Chemistry for taiya

Question

. How much heat is absorbed during photosynthesis when 525 mg of glucose C6H12O6 is produced?
6CO2 + 6H2O --> C6H12O6 + 6O2 ∆H = +2803 kJ/mol

Answer 1

Calculate number of moles of glucose

525*10^-3g/180 g/mole = 0.0029 moles;

The amount of heat will be calculated as

( 2803 kJ/mole) *0.0029 mole = 8.13 kJ