Ca(OH)2 + 2HCl —> CaCl2 + 2H2O
0.15N (HCl) = 0.015kg = 15g
No of moles of HCl = 15/(2*35.5) = 15/71 = 0.211mol/dm3
With HCl as the limiting reagent
and molar mass of CaCl2 as 111g/mol
Mass of CaCl2 therefore formed = 0.211*111 = 23.45g = 0.023kg
The weight of CaCl2 is 0.23N
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