Combustion of diborane is occur according to the following equation,
B2H6 + 3O2 ----> B2O3 + 3H2O
Heat of combustion, ∆H = –2035 kJ/mol
(–) is due to liberation of heat
The heat absorbs by the calorimeter,
H = 2035 kJ
Heat capacity of calorimeter,S = 7.854 kJ/°C
Initial temperature of calorimeter,
T1 = 23.60°C
Let, final temperature of calorimeter = T2°C
So, H = S×(T2–T1)
Or, (T2–T1) = H/S
Or, T2 = (H/S) + T1
= [(2035/7.854)+23.70]
= 282.7 ° C
Hence, find temperature of calorimeter is 282.7 °C.
Comments
Leave a comment