Question

A 47 g of unknown material was heated from 22 degrees to 156 degrees. This process required 2.796kj of energy.

The block was made from which material based on the S (specific heat capacity value?

Copper S= 0.385 J g^-1 degrees^-1
Olive Oil S = 2.000 J g^-1 degrees ^-1
Mercury S= 0.140J g^-1 degrees^-1
Gold S= 0.129J g^-1 degrees^-1
Lead S = 0.160 J g^-1 degrees^-1
Iron S= 0.444 J g^-1 degrees^-1
Marble S= 0.880 J g^-1 degrees^-1
Aluminium= 0.900 J g^-1 degrees^-1

Answer 1

$\frac{2.796×1000}{47×(156-22)}=0.444.$

The material is iron.