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Answer to Question #148293 in General Chemistry for liam donohue
Question #148293
A Christmas LED bulb burned for 24 hours and consumed 6532KJ during this period.
What is the wattage or watt (W) rating of this lead?
What is the wattage or watt (W) rating of this lead?
Expert's answer
Power(kW)= Energy(kJ)/Time(s)
24hours= 86400s
∴ Power = 6532/86400
= 0.0756kW
= 75.6W
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