Answer to Question #148143 in General Chemistry for rae

Question

What is the molarity of a solution that contains 0.350 g of barium fluoride, BaF2, in 0.50 L of solution

Answer 1

Mass of BaF₂= 0.350g

Molar mass of BaF₂= 137.34 + (19x2)= 175.34gmol^-1

Moles of BaF₂= mass/molar mass

Moles of BaF₂= 0.350/175.34= 2.0 x 10^-3mol

Volume of solution = 0.50L

Molarity = moles of solute/litres of solution

Molarity = 2.0 x10^-3mol/ 0.5L

Molarity= 4.0 x 10^-3M