What is the final temperature of the water if 35.1 kJ of energy are added to 100.0 g of ice at -4.5°C?
Quantity of Heat= mici(Tfi-Tii) + mLf + mwcw(Tfw-Tiw)
35.1= 0.1×2.04× (0- -4.5) + 0.1×335 +0.1×4.184(Tfw-0)
35.1= 0.918 + 33.5 +0.4184 Tfw
35.1-34.418= 0.4184 Tfw
0.682/0.4184= Tfw
Tfw= 1.63 °C
Comments
Leave a comment