n(NaOH)=0,54 mole
m(NaOH)=n(NaOH)∗M(NaOH)m(NaOH)=n(NaOH)*M(NaOH)m(NaOH)=n(NaOH)∗M(NaOH)
m(NaOH)=0,54*(23+16+1)=21,6 g
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment