Question

If 96.0 mL of nitrogen gas reacts with 42.0 mL of oxygen gas, what is the volume of NO2 produced? Assume all gases are at the same temperature and pressure.

N2(g)+O2(g)→NO2(g)

Answer 1

N2(g)+2O2(g)→2NO2(g)

we have the excess of nitrogen so calculate everything from oxygen volume

V(O2)=V(NO2) from stoichiometric coefficients

V(NO2)=42mL