Answer to Question #147787 in General Chemistry for jaylin

Question

How many grams of chlorine gas must react to give 3.72 g of BiCl3?
2Bi(s)+3Cl2(g)→2BiCl3(s)
Express your answer with the appropriate units.

Answer 1

2 BiCl₃ = 3 Cl₂

2(315.34g) BiCl₃ = 3(70.9 g) Cl₂

1g BiCl₃ = 3 ×70.9 /(2×315.34)g Cl₂

3.72g = (3 ×70.9 × 3.72) /(2 ×315.34g) Cl₂

= 1.25g