Answer to Question #147525 in General Chemistry for Kathlyn albao

Question #147525
How many moles of NaAlO2 is produced if 126.4 g of NaOH reacts completely?
1
Expert's answer
2020-12-01T09:03:23-0500

2Al+2NaOH+2H2O2NaAlO2+3H22Al+2NaOH+2H2O→2NaAlO2+3H2

MolarMassof2NaAlO2=(2×23)+(2×27)+(2×48)Molar Mass of 2NaAlO2=(2×23)+(2×27)+(2×48)

=196g/mol=196g/mol

Moles=Mass/MolarMassMoles=Mass/Molar Mass

=126.4g/196g/mol=126.4g/196g/mol

=0.748MolNaAlO2=0.748Mol NaAlO2


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