In a 0.15 M NH3 solution, what percent of the NH3 is present as NH4
+? (Kb = 1.8 x 10^-5)
Kb= a^2c. a= √(Kb/c)
a= √(1.8 x 10^-5/0.15)=0,0282842712.
W%= 0,0282842712 x 100 % = 2,82842712%.
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